At t = 0, assume that the output of the digital to analog converter (DAC)
is zero, then if Vin = (1/2)Vin(max), Vc will be negative which makes the
comparator output high, which produces a Vin(max) at the output of the DAC,
which makes a negative input into the integrator, producing a positive Vc,
making the comparator output low, causing the output of the DAC to be zero,
and the cycle repeats as with t = 0. Similar analysis can be done with Vin =
0 and Vin = Vin(max). The results are as follows:
Vin = 0
=> Output = 000000...
Vin = (1/2)Vin(max)
=> Output = 101010...
Vin = Vin(max)
=> Output = 111111...
Thus, the higher the input voltage, the greater the prevalence of one's at the serial digital output.